(x^2+x-12)/(x^2-16)

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Solution for (x^2+x-12)/(x^2-16) equation: 


D( x )

x^2-16 = 0

x^2-16 = 0

x^2-16 = 0

1*x^2 = 16 // : 1

x^2 = 16

x^2 = 16 // ^ 1/2

abs(x) = 4

x = 4 or x = -4

x in (-oo:-4) U (-4:4) U (4:+oo)

(x^2+x-12)/(x^2-16) = 0

x^2+x-12 = 0

x^2+x-12 = 0

DELTA = 1^2-(-12*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-1)/(1*2) or x = (-49^(1/2)-1)/(1*2)

x = 3 or x = -4

(x+4)*(x-3) = 0

((x+4)*(x-3))/(x^2-16) = 0

( x+4 )

x+4 = 0 // - 4

x = -4

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -4} 

x = 3

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